Date :: subtractMonths - Subtract month from date value
The function subtracts a number of months from the current date and returns the new date value.
Return value: Date ( odaba::Date & )
The date contains day, month and year, but not the time.
Implementation details
odaba::Date &
Date :: subtractMonths ( int32 iMonths )
The number of months passed in iMonths is subtracted from the date value. Year may change, when month becomes less than 1. Usually, day remains unchanged, but will be adjusted, when the new month value does not have the resulting day
- iMonths
- Months
Time span in months.