Date :: subtractMonths - Subtract month from date value
The number of months passed in iMonths is subtracted from the date value. Year may change, when month becomes less than 1 . Usually, day remains unchanged, but will be adjusted, when the new month value does not have the resulting day
Date date(31,3,2009);
date.subtractMonths(1); // day becomes: 2009-28-2
Return value: Date ( odaba::Date & )
The date contains day, month and year, but not the time.
Implementation details
odaba::Date &
Date  :: subtractMonths ( int32 iMonths )
- iMonths
- Months
Time span in months.